Question

1. if the diagonal of a square is 11.3 meters, approximately what is the perimeter of the square?

Explanation:

Step1: Find the side length of the square

Let the side length of the square be \(a\). According to the Pythagorean theorem, for a square with diagonal \(d\), \(d^{2}=a^{2}+a^{2}=2a^{2}\). Given \(d = 11.3\) meters, then \(a^{2}=\frac{d^{2}}{2}=\frac{11.3^{2}}{2}=\frac{127.69}{2}=63.845\), and \(a=\sqrt{63.845}\approx 8\) meters.

Step2: Calculate the perimeter of the square

The perimeter formula of a square is \(P = 4a\). Substituting \(a\approx8\) meters into the formula, we get \(P=4\times8 = 32\) meters.

Answer:

32 meters