Question

(04.02 lc)
solve the following system of equations:
x + 3y = -4
x + 5y = -6

○ (1, 1)
○ (-1, 1)
○ (1, -1)
○ (-1, -1)

Explanation:

Step1: Subtract the two equations

Subtract the first equation \( x + 3y = -4 \) from the second equation \( x + 5y = -6 \).

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Step2: Solve for y

Divide both sides of \( 2y = -2 \) by 2.

$$ y = \frac{-2}{2} = -1 $$

Step3: Substitute y into first equation

Substitute \( y = -1 \) into \( x + 3y = -4 \).

$$ x + 3(-1) = -4\\ x - 3 = -4 $$

Step4: Solve for x

Add 3 to both sides of \( x - 3 = -4 \).

$$ x = -4 + 3 = -1 $$

Answer:

\((-1, -1)\)