Question

a 7.00 kg bowling ball is held 2.00 m above the ground. using g = 9.80 m/s², how much energy does the bowling ball have due to its position?
68.6 j
137 j
274 j
960 j

Explanation:

Step1: Identify the formula

The energy due to position is gravitational - potential energy, $U = mgh$.

Step2: Substitute the values

Given $m = 7.00\ kg$, $g=9.80\ m/s^{2}$, $h = 2.00\ m$. Then $U=7.00\times9.80\times2.00$.

Step3: Calculate the result

$U = 137.2\ J\approx137\ J$.

Answer:

137 J