Question

the zookeeper must heat the zogbug’s cage to 50 degrees. how many degrees warmer did the zookeeper have to make the cage at 3 oclock?
? degrees
hourly temperature
temp (°c)
8 am 10 am 12 pm 2 pm 4

Explanation:

Step1: Find temperature at 3 o'clock

Looking at the "Hourly Temperature" graph, at 3 o'clock (assuming the x - axis progression: 8 am, 9 am (20°C), 10 am (45°C), 11 am (50°C), 12 pm (50°C), 1 pm (45°C), 2 pm (45°C), 3 pm (30°C)? Wait, maybe the time labels: 8 am, then 9 am (the second point, 20°C), 10 am (45°C), 11 am (50°C), 12 pm (50°C), 1 pm (45°C), 2 pm (45°C), 3 pm (30°C)? Wait, no, maybe the x - axis is 8 am, 9 am, 10 am, 11 am, 12 pm, 1 pm, 2 pm, 3 pm, 4 pm. Wait, the first point is 8 am (10°C), second 9 am (20°C), third 10 am (45°C), fourth 11 am (50°C), fifth 12 pm (50°C), sixth 1 pm (45°C), seventh 2 pm (45°C), eighth 3 pm (30°C)? Wait, no, the problem says "at 3 o'clock". Wait, maybe I misread. Wait, the target is 50 degrees. Wait, no, the question is "How many degrees warmer did the zookeeper have to make the cage at 3 o'clock?". So we need to find the temperature at 3 o'clock from the graph and subtract it from 50. Wait, looking at the graph, at 3 o'clock (assuming the x - axis: 8 am, 9 am, 10 am, 11 am, 12 pm, 1 pm, 2 pm, 3 pm). Let's check the y - axis. The points: 8 am: 10°C, 9 am: 20°C, 10 am: 45°C, 11 am: 50°C, 12 pm: 50°C, 1 pm: 45°C, 2 pm: 45°C, 3 pm: 30°C? Wait, no, maybe the 3 o'clock point is 30°C? Wait, no, maybe I made a mistake. Wait, the graph: the y - axis is Temp (°C), with 10,15,20,25,30,35,40,45,50. The points: first (8 am) at 10, second (9 am) at 20, third (10 am) at 45, fourth (11 am) at 50, fifth (12 pm) at 50, sixth (1 pm) at 45, seventh (2 pm) at 45, eighth (3 pm) at 30? Wait, no, maybe the 3 o'clock is the point at 30? Wait, no, the question is to heat to 50 degrees. So the temperature at 3 o'clock: let's see, the graph has a point at 30°C at 3 pm? Wait, no, maybe the x - axis labels are 8 am, 10 am, 12 pm, 2 pm, 4 pm? No, the first label is 8 am, then 10 am, 12 pm, 2 pm, 4 pm? Wait, the distance between 8 am and 10 am is 2 hours, so maybe each grid is 1 hour. So 8 am, 9 am, 10 am, 11 am, 12 pm, 1 pm, 2 pm, 3 pm, 4 pm. So at 3 pm, the temperature is 30°C? Wait, no, the point at 3 pm (the eighth point) is at 30°C? Wait, no, the seventh point is 2 pm at 45°C, then the eighth is 3 pm at 30°C? Wait, no, the line goes from 2 pm (45°C) down to 3 pm (30°C)? Wait, no, the graph: from 2 pm (45°C) to 3 pm (30°C)? Wait, no, the y - axis: 45, then 40, 35, 30. So the point at 3 pm is 30°C? Wait, no, maybe I'm wrong. Wait, the target is 50°C. So 50 - 30 = 20? No, wait, maybe the temperature at 3 o'clock is 30°C? Wait, no, let's re - examine. Wait, the first point: 8 am (10°C), second: 9 am (20°C), third: 10 am (45°C), fourth: 11 am (50°C), fifth: 12 pm (50°C), sixth: 1 pm (45°C), seventh: 2 pm (45°C), eighth: 3 pm (30°C). So the temperature at 3 pm is 30°C. Then the number of degrees warmer needed is 50 - 30 = 20? Wait, no, maybe I misread the time. Wait, maybe "at 3 o'clock" is a typo, maybe "at 9 o'clock"? No, the problem says 3 o'clock. Wait, no, maybe the graph's 3 o'clock is 30°C. Wait, but let's check again. Wait, the y - axis: the horizontal lines are at 10,20,30,40,45,50. The points: 8 am: 10, 9 am: 20, 10 am: 45, 11 am: 50, 12 pm: 50, 1 pm: 45, 2 pm: 45, 3 pm: 30, 4 pm: 10. So at 3 pm, temperature is 30°C. Target is 50°C. So 50 - 30 = 20? Wait, no, maybe I made a mistake in the time. Wait, maybe the x - axis is 8 am, 10 am, 12 pm, 2 pm, 4 pm, so 3 pm is between 2 pm and 4 pm. The point at 3 pm is 30°C. So 50 - 30 = 20. Wait, but maybe the temperature at 3 o'clock is 30, so 50 - 30 = 20.

Step2: Calculate the difference

The target temperature is 50°C. The temperature at 3 o'clock (from the graph) is 30°C. So the number of degrees warmer needed is $50 - 30 = 20$.

Answer:

20