Question

youre trying to figure out how many solutions the equation has. lets solve this equation step by step. youre trying to get rid of the parentheses on the left by distributing the \\(\frac{1}{2}\\) to the 6x and to the 2. you can think of this as \\(\left(\frac{1}{2} \cdot 6x\
ight) + \left(\frac{1}{2} \cdot 2\
ight)\\). \\(\frac{1}{2}(6x + 2) = 3x\\) \\(\square + \square = 3x\\)

Explanation:

Step1: Distribute $\frac{1}{2}$ to $6x$

Multiply $\frac{1}{2}$ and $6x$: $\frac{1}{2} \cdot 6x = 3x$

Step2: Distribute $\frac{1}{2}$ to $2$

Multiply $\frac{1}{2}$ and $2$: $\frac{1}{2} \cdot 2 = 1$

Answer:

$3x + 1 = 3x$