Question

you play a game that requires rolling a six - sided die then randomly choosing a colored card from a deck containing 2 red cards, 10 blue cards, and 5 yellow cards. find the probability that you the die and then choose a blue card.

a (\frac{16}{17})

b (\frac{5}{8})

c (\frac{5}{10})

d (\frac{1}{17})

Explanation:

Step1: Find total cards

Total cards = 2 (red) + 10 (blue) + 5 (yellow) = 17.

Step2: Probability of blue card

Probability of blue card = $\frac{\text{Blue cards}}{\text{Total cards}}$ = $\frac{10}{17}$? Wait, no, wait the problem is rolling a die and choosing a blue card. Wait, rolling a die: probability of any outcome on a six - sided die is $\frac{1}{6}$? Wait no, maybe the problem is "roll a die (any outcome) and then choose a blue card". Wait, the card deck: 2 red, 10 blue, 5 yellow. Total cards = 2 + 10+5 = 17. Probability of choosing blue card is $\frac{10}{17}$. But wait, maybe the die part is a distractor? Wait, no, maybe the problem is "roll a die (success?) and then choose blue". Wait, maybe the original problem was "roll a die and get a certain number, then choose blue", but the text is cut. Wait, looking at the options, option A is $\frac{10}{17}$, option B is $\frac{5}{8}$, option C is $\frac{1}{10}$, option D is $\frac{1}{17}$. Wait, total cards: 2 + 10+5 = 17. Blue cards: 10. So probability of choosing blue card is $\frac{10}{17}$. So the correct option is A.

Answer:

A. $\frac{10}{17}$