Question

write the standard equation of the circle with
center:$(-11,-8)$
radius: 4
equation:

Explanation:

Step1: Recall the standard equation of a circle

The standard equation of a circle is \((x - h)^2+(y - k)^2=r^2\), where \((h,k)\) is the center and \(r\) is the radius.

Step2: Substitute the values of \(h\), \(k\), and \(r\)

Given \(h=-11\), \(k = - 8\), and \(r = 4\).
Substituting into the formula: \((x-(-11))^2+(y-(-8))^2=4^2\).
Simplify the equation: \((x + 11)^2+(y + 8)^2=16\).

Answer:

\((x + 11)^2+(y + 8)^2=16\)