Question

write the ratio for sin x. triangle with right angle at i, sides: iz=6, ix=8, zx=10

Explanation:

Step1: Recall sine definition

In a right triangle, $\sin(\theta) = \frac{\text{opposite}}{\text{hypotenuse}}$.

Step2: Identify sides for $\angle X$

For $\angle X$, opposite side is $ZI = 6$, hypotenuse is $XZ = 10$.

Step3: Write the ratio

$\sin(X) = \frac{6}{10}=\frac{3}{5}$.

Answer:

$\frac{3}{5}$ (or $\frac{6}{10}$)