QUESTION IMAGE
Question
write the equation of the line in slope-intercept form, $y = mx + b$.
Step1: Identify the y-intercept (b)
The line crosses the y-axis at (0, -2), so \( b = -2 \).
Step2: Calculate the slope (m)
Use two points, e.g., (0, -2) and (1, 1) (wait, no, let's check the graph again. Wait, from (0, -2) to (1, 1)? Wait, no, looking at the grid, when x increases by 1, y increases by 3? Wait, no, let's take (0, -2) and (1, 1)? Wait, no, maybe (0, -2) and (1, 1) is wrong. Wait, actually, from (0, -2) to (1, 1)? Wait, no, let's count the rise over run. From (0, -2) to (1, 1)? Wait, no, the line goes through (0, -2) and (1, 1)? Wait, no, when x=0, y=-2; when x=1, y=1? Wait, no, the slope: let's take two points. Let's take (0, -2) and (1, 1)? Wait, no, maybe (0, -2) and (1, 1) is incorrect. Wait, actually, looking at the graph, the line passes through (0, -2) and (1, 1)? Wait, no, when x increases by 1, y increases by 3? Wait, no, let's do it properly. The slope formula is \( m = \frac{y_2 - y_1}{x_2 - x_1} \). Let's take two points: (0, -2) and (1, 1)? Wait, no, when x=0, y=-2; when x=1, y=1? Wait, no, the line goes through (0, -2) and (1, 1)? Wait, no, maybe (0, -2) and (1, 1) is wrong. Wait, actually, from (0, -2) to (1, 1) is a rise of 3 and run of 1, so slope is 3? Wait, no, let's check the graph again. Wait, the line passes through (0, -2) and (1, 1)? Wait, no, when x=1, y=1? Wait, no, the grid: each square is 1 unit. So from (0, -2) to (1, 1): y increases by 3, x increases by 1, so slope is 3? Wait, no, wait, when x=0, y=-2; when x=1, y=1? Wait, no, the line is steeper. Wait, maybe (0, -2) and (1, 1) is wrong. Wait, let's take (0, -2) and (1, 1) – no, maybe (0, -2) and (1, 1) is incorrect. Wait, actually, the line passes through (0, -2) and (1, 1)? Wait, no, let's count the slope. From (0, -2) to (1, 1): rise is 3, run is 1, so slope is 3? Wait, no, that can't be. Wait, maybe I made a mistake. Wait, the line goes through (0, -2) and (1, 1)? Wait, no, when x=1, y=1? Wait, the graph shows that when x=1, y is 1? Wait, no, the line is going up steeply. Wait, actually, the slope is 3? Wait, no, let's check the y-intercept first. The y-intercept (b) is -2, as the line crosses the y-axis at (0, -2). Now, let's find the slope. Let's take two points: (0, -2) and (1, 1). Then \( m = \frac{1 - (-2)}{1 - 0} = \frac{3}{1} = 3 \). Wait, but the keypad has 3, so maybe the slope is 3. So the equation is \( y = 3x - 2 \). Wait, let's check: when x=0, y=-2 (correct). When x=1, y=3(1) -2 =1 (correct, as per the graph). When x=2, y=3(2)-2=4 (which matches the graph, as at x=2, y=4). So yes, slope is 3, y-intercept is -2.
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\( y = 3x - 2 \)