Question

write equation of the line containing (-3,4) and (-1,-2)
y = 3x + 1
y = -3x - 5
y = -3x + 13
y = -3x + 1

Explanation:

Step1: Calculate the slope

The slope $m$ formula is $m=\frac{y_2 - y_1}{x_2 - x_1}$. Let $(x_1,y_1)=(-3,4)$ and $(x_2,y_2)=(-1,-2)$. Then $m=\frac{-2 - 4}{-1-(-3)}=\frac{-6}{2}=-3$.

Step2: Use the point - slope form

The point - slope form is $y - y_1=m(x - x_1)$. Using the point $(-3,4)$ and $m = - 3$, we have $y - 4=-3(x+3)$.

Step3: Simplify the equation

Expand the right - hand side: $y - 4=-3x-9$. Add 4 to both sides to get $y=-3x - 5$.

Answer:

$y=-3x - 5$