Question

write the equation of the circle centered at (-9,6) with radius 14. question help: video

Explanation:

Step1: Recall the standard form of a circle's equation

The standard form of a circle's equation is \((x - h)^2+(y - k)^2=r^2\), where \((h,k)\) is the center and \(r\) is the radius.

Step2: Substitute the given values into the formula

Given \(h=-9\), \(k = 6\), and \(r = 14\).
Substitute into \((x - h)^2+(y - k)^2=r^2\):
\((x-(-9))^2+(y - 6)^2=14^2\)
Simplify \((x + 9)^2+(y - 6)^2=196\)

Answer:

\((x + 9)^2+(y - 6)^2=196\)