QUESTION IMAGE
Question
write each as an expression and simplify.
- an investment of $500 doubles monthly for 2 years.
- an investment of $1,000 tripled quarterly for 2 years.
- an investment of $5,000 triples every 6 months for 2 years.
- which is the best investment? circle the correct choice.
1 2 3
Step1: Calculate the number of periods for each investment
- For investment 1: 2 years = 24 months. Since it doubles monthly, the number of periods \(n_1=24\).
- For investment 2: 2 years = 8 quarters. Since it triples quarterly, the number of periods \(n_2 = 8\).
- For investment 3: 2 years = 4 half - years. Since it triples every 6 months, the number of periods \(n_3=4\).
Step2: Use the compound - growth formula \(A = P\times r^n\) (where \(P\) is the principal, \(r\) is the growth factor per period, and \(n\) is the number of periods)
- Investment 1: \(P_1=\$500\), \(r_1 = 2\) (doubles), \(n_1=24\)
\(A_1=500\times2^{24}\)
\(A_1=500\times16777216=\$8388608000\)
- Investment 2: \(P_2 = \$1000\), \(r_2=3\) (triples), \(n_2 = 8\)
\(A_2=1000\times3^{8}\)
\(A_2=1000\times6561=\$6561000\)
- Investment 3: \(P_3=\$5000\), \(r_3 = 3\) (triples), \(n_3=4\)
\(A_3=5000\times3^{4}\)
\(A_3=5000\times81=\$405000\)
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The best investment is 1.