Question

which value is equivalent to \\(\frac{7^{-3}}{7^{-5}}\\)?

\\(\bigcirc\\) \\(7^{8}\\)
\\(\bigcirc\\) \\(7^{15}\\)
\\(\bigcirc\\) \\(7^{-2}\\)
\\(\bigcirc\\) \\(7^{2}\\)

Explanation:

Step1: Identify the expression

$$\frac{7^{-3}}{7^{-5}}$$

Step2: Apply quotient rule

$$7^{-3 - (-5)}$$

Step3: Simplify the exponent

$$7^{-3 + 5} = 7^{2}$$

Answer:

\(7^{2}\)