QUESTION IMAGE
Question
which table shows a proportional relationship between x and y?
a
| x | y |
|---|---|
| 2 | 3 |
| 3 | 6 |
b
| x | y |
|---|---|
| 2 | 3 |
| 3 | 5 |
c
| x | y |
|---|---|
| 2 | 4 |
| 3 | 6 |
(part of table d is shown but cut off)
Step1: Recall Proportional Relationship
A proportional relationship between \( x \) and \( y \) means \( y = kx \) (where \( k \) is a constant), so \( \frac{y}{x}=k \) for all pairs \((x,y)\) (and \( x
eq0 \)). Also, when \( x = 0 \), \( y \) should be \( 0 \) (though not all tables have \( x = 0 \), the ratio \( \frac{y}{x} \) must be constant).
Step2: Check Option A
For table A:
- When \( x = 1 \), \( y = 0 \), \( \frac{y}{x}=\frac{0}{1}=0 \)
- When \( x = 2 \), \( y = 3 \), \( \frac{y}{x}=\frac{3}{2}=1.5 \)
- Ratios are not equal, so not proportional.
Step3: Check Option B
For table B:
- When \( x = 1 \), \( y = 1 \), \( \frac{y}{x}=1 \)
- When \( x = 2 \), \( y = 3 \), \( \frac{y}{x}=\frac{3}{2}=1.5 \)
- Ratios are not equal, so not proportional.
Step4: Check Option C
For table C:
- When \( x = 1 \), \( y = 2 \), \( \frac{y}{x}=\frac{2}{1}=2 \)
- When \( x = 2 \), \( y = 4 \), \( \frac{y}{x}=\frac{4}{2}=2 \)
- When \( x = 3 \), \( y = 6 \), \( \frac{y}{x}=\frac{6}{3}=2 \)
- Ratios are equal (\( k = 2 \)), so proportional.
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C. The table with \( x = 1, y = 2 \); \( x = 2, y = 4 \); \( x = 3, y = 6 \)