Question

1. which step in the proof has a flaw? given b is the midpoint of \\( \overline { a c } \\), prove \\( \overline { a b } \cong \overline { b c } \\).

no flaws. step 3 step 1 step 2

Explanation:

Step1: Recall the definition of mid - point

If \(B\) is the mid - point of \(\overline{AC}\), by the definition of mid - point, \(AB = BC\) (in terms of length). The symmetric property of congruence states that if \(a\cong b\), then \(b\cong a\). But we need to first establish the congruence using the mid - point definition.
The correct step after \(B\) is the mid - point of \(\overline{AC}\) (Step 1) should be using the mid - point theorem (a point \(B\) being the mid - point of a line segment \(\overline{AC}\) implies \(\overline{AB}\cong\overline{BC}\)) not the symmetric property.

Answer:

Step 2