Question

2 which statement best describes the motion of th and 8 seconds?
me graph
a the object is negatively accelerating.
b the object is positively accelerating.
c the object is stopped.
d the object is moving at a constant velocity.
igh below to answer the questions.

Explanation:

Step1: Analyze the velocity - time graph

In a velocity - time graph, acceleration is the slope of the graph. The formula for acceleration is \(a=\frac{\Delta v}{\Delta t}\), where \(\Delta v = v_{final}-v_{initial}\) and \(\Delta t=t_{final}-t_{initial}\).

Step2: Check the slope between 6 and 8 seconds

From \(t = 6\) s to \(t=8\) s, the velocity \(v\) is constant. So, \(\Delta v=v(8)-v(6)=0\). Using the acceleration formula \(a = \frac{\Delta v}{\Delta t}\), with \(\Delta v = 0\) and \(\Delta t>0\), we get \(a = 0\). When \(a = 0\), the object is moving at a constant velocity.

Answer:

D. The object is moving at a constant velocity.