Question

which has more mechanical energy - a 40 kg rock 12 meters off the ground, or a 10 kg ball traveling 87 m/s?
1 response

$ke = \frac{mv^{2}}{2}$ or $ke = \frac{1}{2}mv^{2}$ $pe = mgh$ where $g = 9.8 m/s^{2}$ $pe_{max}=ke_{max}$

ball
rock
equal

Explanation:

Step1: Calculate the potential energy of the rock

The formula for potential energy is \(PE = mgh\). Given \(m = 40\space kg\), \(g=9.8\space m/s^{2}\), \(h = 12\space m\).

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Step2: Calculate the kinetic energy of the ball

The formula for kinetic energy is \(KE=\frac{1}{2}mv^{2}\). Given \(m = 10\space kg\), \(v = 87\space m/s\).

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Answer:

ball