Question

which graph represents the solutions to this inequality? 8v - 15 ≥ -39 and 3v + 4 < 61

Explanation:

Step1: Solve \(8v - 15\geq - 39\)

Add \(15\) to both sides: \(8v\geq - 39 + 15\), so \(8v\geq - 24\).
Divide both sides by \(8\): \(v\geq - 3\).

Step2: Solve \(3v + 4\lt61\)

Subtract \(4\) from both sides: \(3v\lt61 - 4\), so \(3v\lt57\).
Divide both sides by \(3\): \(v\lt19\).

Answer:

The solution of the compound inequality \(8v - 15\geq - 39\) and \(3v + 4\lt61\) is \(-3\leq v\lt19\). So the graph with a closed circle at \(-3\) (because \(v = - 3\) is included) and an open circle at \(19\) (because \(v=19\) is not included) and the line segment between them is the correct one.