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which equation is the inverse of \\(2(x - 2)^2 = 8(7 + y)\\)? \\(-2(x -…

Question

which equation is the inverse of \\(2(x - 2)^2 = 8(7 + y)\\)?

\\(-2(x - 2)^2 = -8(7 + y)\\)

\\(y = \frac{1}{4}x^2 - x - 6\\)

\\(y = -2 \pm \sqrt{28 + 4x}\\)

\\(y = 2 \pm \sqrt{28 + 4x}\\)

Explanation:

Swap variables x and y

$$ 2(y-2)^2 = 8(7+x) $$

Isolate the squared term

$$ (y-2)^2 = 4(7+x) = 28 + 4x $$

Solve for y

$$ LATEXBLOCK0 $$

Answer:

  • (A) \(-2(x-2)^2 = -8(7+y)\)
  • (B) \(y = \frac{1}{4}x^2 - x - 6\)
  • (C) \(y = -2 \pm \sqrt{28+4x}\)
  • (D) \(y = 2 \pm \sqrt{28+4x}\) (Correct answer)