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Question
which equation is the inverse of \\(2(x - 2)^2 = 8(7 + y)\\)?
\\(-2(x - 2)^2 = -8(7 + y)\\)
\\(y = \frac{1}{4}x^2 - x - 6\\)
\\(y = -2 \pm \sqrt{28 + 4x}\\)
\\(y = 2 \pm \sqrt{28 + 4x}\\)
Swap variables x and y
$$
2(y-2)^2 = 8(7+x)
$$
Isolate the squared term
$$
(y-2)^2 = 4(7+x) = 28 + 4x
$$
Solve for y
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- (A) \(-2(x-2)^2 = -8(7+y)\)
- (B) \(y = \frac{1}{4}x^2 - x - 6\)
- (C) \(y = -2 \pm \sqrt{28+4x}\)
- (D) \(y = 2 \pm \sqrt{28+4x}\) (Correct answer)