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which is the best approximation of the value of x? use the law of sines…

Question

which is the best approximation of the value of x? use the law of sines to find the answer. 1.5 units 2.1 units law of sines: $\frac{sin(a)}{a}=\frac{sin(b)}{b}=\frac{sin(c)}{c}$

Explanation:

Response
  1. First, find the third - angle of the triangle:
  • The sum of the interior angles of a triangle is \(180^{\circ}\). Given two angles \(A = 75^{\circ}\) and \(B = 50^{\circ}\), the third - angle \(C=180-(75 + 50)=55^{\circ}\).
  • By the law of sines, \(\frac{\sin A}{a}=\frac{\sin B}{b}=\frac{\sin C}{c}\). Let the side opposite the \(75^{\circ}\) angle be \(a = 2\), the side opposite the \(50^{\circ}\) angle be \(b=x\), and the side opposite the \(55^{\circ}\) angle be \(c\).
  • Using the law of sines \(\frac{\sin A}{a}=\frac{\sin B}{b}\), we substitute \(A = 75^{\circ}\), \(a = 2\), and \(B = 50^{\circ}\), \(b=x\).
  • So, \(\frac{\sin75^{\circ}}{2}=\frac{\sin50^{\circ}}{x}\).
  • We know that \(\sin75^{\circ}=\sin(45^{\circ}+30^{\circ})=\sin45^{\circ}\cos30^{\circ}+\cos45^{\circ}\sin30^{\circ}=\frac{\sqrt{2}}{2}\times\frac{\sqrt{3}}{2}+\frac{\sqrt{2}}{2}\times\frac{1}{2}=\frac{\sqrt{6}+\sqrt{2}}{4}\approx\frac{2.449 + 1.414}{4}=\frac{3.863}{4}=0.966\), and \(\sin50^{\circ}\approx0.766\).
  • Then, from \(\frac{\sin75^{\circ}}{2}=\frac{\sin50^{\circ}}{x}\), we can cross - multiply to get \(x\times\sin75^{\circ}=2\times\sin50^{\circ}\).
  • \(x=\frac{2\times\sin50^{\circ}}{\sin75^{\circ}}\).
  • Substituting the approximate values of \(\sin50^{\circ}\) and \(\sin75^{\circ}\), we have \(x=\frac{2\times0.766}{0.966}\approx1.58\approx1.6\). The closest value to \(1.6\) among the options is \(1.5\) units.

Answer:

1.5 units