where else? emiliano’s first guess (shown in red) hit part of the long boat (1x3) from the previous screen. which of the following could yield another hit on that same boat? (select all that apply.) (-2,0) (1,-1) (1,0) (-1,1)

Question

Accepted Answer

# Brief Explanations:
The red rectangle (the boat) is a 1x3 (assuming length along x - axis or y - axis? Wait, looking at the grid, the red square (maybe a 1x1? No, the problem says 1x3 long boat). Wait, the first guess is a red rectangle. Let's analyze the coordinates. The boat is probably horizontal or vertical. Let's check the given points:

- For $(-2,0)$: If the boat is horizontal (length along x - axis), the original red area is around x from - 1 to 1 (maybe) and y from 0 to 1? Wait, the red square is between x=-1 to 1? No, the grid: the red rectangle is centered at x = 0, y = 0? Wait, the coordinates: let's see the options. The boat is a 1x3, so it has a length of 3 units. Let's check the x - coordinates. The original hit is in red. Let's see the x - range. If the boat is horizontal (along x - axis), then the x - coordinates of the boat should be consecutive. Let's check each point:

- $(-2,0)$: If the boat is from x=-2 to x = 0 (length 3) or x=-1 to x = 1 (no, 1x3 would be length 3). Wait, maybe the boat is horizontal with length 3, so the x - coordinates differ by 2 (since 1x3, the length in x - direction is 3, so the x - values of the boat's cells are consecutive with a difference of 1 between them, and the total length is 3). Wait, the original red area: looking at the grid, the red rectangle is at x from - 1 to 1 (maybe) and y from 0 to 1? No, the options are $(-2,0)$, $(1,0)$, $(1, - 1)$, $(-1,1)$.

Wait, the boat is a 1x3 (so 3 cells long, 1 cell wide). Let's assume it's horizontal (same y - coordinate). The original hit is in the red area. Let's check the y - coordinate of the red area. From the grid, the red rectangle is at y = 0 (since the center is at (0,0) maybe). So the boat is horizontal, y = 0, and x from - 1 to 1? No, 1x3 would be x from - 2 to 0, or - 1 to 1 (no, 3 cells: x=-1, 0, 1? That's 3 cells, length 3). Wait, the red area is at x=-1, 0, 1 and y = 0? No, the red square in the grid: looking at the image, the red rectangle is between x=-1 to 1 (x - axis) and y = 0 to 1 (y - axis)? No, the options have y = 0 for $(-2,0)$ and $(1,0)$, y=-1 for $(1, - 1)$, y = 1 for $(-1,1)$.

Wait, the boat is a 1x3, so it has a constant y - coordinate (horizontal) or constant x - coordinate (vertical). Let's check the original red area: in the grid, the red rectangle is at x around - 1, 0, 1 (x - axis) and y around 0 (y - axis). So if it's horizontal (y = 0), the x - coordinates of the boat's cells are - 1, 0, 1 (length 3). Now, let's check the options:

- $(-2,0)$: If the boat is from x=-2 to x = 0 (length 3), then (-2,0) would be part of it. But the original red area is at x=-1,0,1? Wait, maybe the boat is shifted. Wait, the original hit is a 1x3, so the boat has length 3. Let's check the x - difference. The original red area: let's say the center is at (0,0), and the boat is horizontal. So the cells are ( - 1,0), (0,0), (1,0). Now, if we move the boat left or right. Wait, the options:

- $(-2,0)$: If the boat is at x=-2, - 1, 0 (y = 0), then (-2,0) is part of it.

- $(1,0)$: If the boat is at x=-1, 0, 1 (y = 0), then (1,0) is part of it.

- $(1, - 1)$: y=-1, different from the original y (0), so not part of the same boat (since it's 1x3, same y - coordinate for horizontal).

- $(-1,1)$: y = 1, different from original y (0), so not part of the same boat.

Wait, maybe the boat is vertical? No, 1x3 vertical would be y from - 1 to 1, x = 0. But the options don't have x = 0, y=-1 or y = 1 except (-1,1) and (1, - 1), which are x≠0.

Wait, re - examining: the red rectangle in the grid is at x from - 1 to 1 (x - axis) and y from 0 to 1 (y - axis)? No, the grid lines: x - axis is vertical, y - axis is horizontal? Wait, maybe I got x and y reversed. Oh! Maybe the x - axis is vertical and y - axis is horizontal. Let's reorient:

If x is vertical (up - down) and y is horizontal (left - right). Then the red rectangle is at x from 0 to 1 (vertical) and y from - 1 to 1 (horizontal). Wait, the options:

- $(-2,0)$: x=-2 (vertical), y = 0 (horizontal). No.

Wait, this is confusing. Let's look at the coordinates:

The options are $(-2,0)$, $(1,0)$, $(1, - 1)$, $(-1,1)$.

The boat is 1x3, so it has a length of 3 in one axis. Let's assume the boat is horizontal (same x - coordinate, length in y - axis). Wait, no, 1x3: 1 unit in one axis, 3 in the other. So if it's 1 (height) x 3 (width), then width is along y - axis, height along x - axis. So x is constant, y from a to a + 2.

Original red area: looking at the grid, the red rectangle is at x = 0 (vertical) and y from - 1 to 1 (horizontal, length 3). So the boat is at x = 0, y=-1, 0, 1. Now check the options:

- $(-2,0)$: x=-2≠0, so no.

- $(1,0)$: x = 1≠0, no.

- $(1, - 1)$: x = 1≠0, no.

- $(-1,1)$: x=-1≠0, no. That can't be.

Wait, maybe the boat is horizontal (y constant, x from a to a + 2). Original red area: y = 0, x from - 1 to 1 (x=-1, 0, 1). So the boat is at y = 0, x=-1, 0, 1. Now check the options:

- $(-2,0)$: y = 0, x=-2. If the boat is at x=-2, - 1, 0 (y = 0), then (-2,0) is part of it.

- $(1,0)$: y = 0, x = 1. Which is part of the original boat (x=-1, 0, 1), so (1,0) is part of it.

- $(1, - 1)$: y=-1≠0, so no.

- $(-1,1)$: y = 1≠0, so no.

So the points with y = 0 (same as the original boat's y - coordinate) and x values that are part of a 3 - length horizontal line. So $(-2,0)$ (if the boat is shifted left) and $(1,0)$ (part of the original boat's x - range) are valid. Wait, but the original red area is a 1x3, so maybe the original hit is one cell, and the boat is 3 cells long. So if the first hit is at (0,0), the boat could be at x=-1,0,1 (y = 0) or x=-2,-1,0 (y = 0). So $(-2,0)$ and $(1,0)$ are part of the boat.

# Answer:
$(-2,0)$, $(1,0)$

Sovi.AI - AI Math Tutor

QUESTION IMAGE

Question

Explanation:

Answer: