Question

when finding the margin of error for the mean of a normally distributed population from a sample, what is the critical probability, assuming a confidence level of 58%? 0.21 0.42 0.58 0.79

Explanation:

Step1: Recall the formula for critical probability

The critical probability \(p^*\) is related to the confidence level \(C\) by the formula \(p^*=\frac{C + 1}{2}\)

Step2: Substitute the confidence level

Given \(C = 0.58\), then \(p^*=\frac{0.58+ 1}{2}\)

$$p^*=\frac{1.58}{2}=0.79$$

Answer:

\(0.79\)