Question

when emma was born she was 20.5 inches long. at her 6-month checkup, she was 26.25 inches long.

emmas length dropdown

\\(\text{percent change} = \frac{\text{amount of change}}{\text{original amount}} = \frac{5.75}{20.5} = 0.2804\\)

the approximate percent change in her length was dropdown.

Explanation:

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<reasoning>

Determine the direction of change

Using the Percent of Change knowledge point
\[

$$\begin{aligned} &\text{Initial length} = 20.5\text{ inches}\\ &\text{Final length} = 26.25\text{ inches}\\ &26.25 > 20.5 \implies \text{increased} \end{aligned}$$

\]

Calculate the approximate percent change

Using the Percent of Change knowledge point
\[

$$\begin{aligned} &\text{Percent Change} = 0.2804\\ &0.2804 \times 100\% = 28.04\% \approx 28\% \end{aligned}$$

\]
</reasoning>

<answer>

Question 1

Emma's length <blank>increased</blank>.

Question 2

The approximate percent change in her length was <blank>28%</blank>.
</answer>

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Answer:

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<reasoning>

Determine the direction of change

Using the Percent of Change knowledge point
\[

$$\begin{aligned} &\text{Initial length} = 20.5\text{ inches}\\ &\text{Final length} = 26.25\text{ inches}\\ &26.25 > 20.5 \implies \text{increased} \end{aligned}$$

\]

Calculate the approximate percent change

Using the Percent of Change knowledge point
\[

$$\begin{aligned} &\text{Percent Change} = 0.2804\\ &0.2804 \times 100\% = 28.04\% \approx 28\% \end{aligned}$$

\]
</reasoning>

<answer>

Question 1

Emma's length <blank>increased</blank>.

Question 2

The approximate percent change in her length was <blank>28%</blank>.
</answer>

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