what is the vertex of the graph of (y = -x^2)?

$(-1, 0)$
$(0, -1)$
$(0, 0)$
$(1, 1)$

Question

what is the vertex of the graph of (y = -x^2)?

$(-1, 0)$
$(0, -1)$
$(0, 0)$
$(1, 1)$

Accepted Answer

{ "quality": "clear", "question_count": 1, "skills_matched": [ "step_cot", "multiple_choice_formatter", "explain_then_answer", "quick" ], "needs_drawing": false, "concepts_used": [ "Vertex of a Quadratic Function" ], "new_concepts": [], "current_concepts": [ "Vertex of a Quadratic Function", "Quadratic Functions" ] } ## Identify the quadratic function form $$ y = -x^2 \implies y = -1(x - 0)^2 + 0 $$ ## Determine the vertex coordinates $$ (h, k) = (0, 0) $$

(-1, 0)

(0, -1)

(0, 0)

(1, 1)

{ "subject": "Mathematics", "question_type": "Multiple Choice", "knowledge_point": [ "Mathematics", "Algebra", "Vertex of a Quadratic Function" ] }

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Question

Explanation:

Identify the quadratic function form

Determine the vertex coordinates

Answer: