Question

what is the value of $a^2 + 3b \div c - 2d$, when $a = 3$, $b = 8$, $c = 2$, and $d = 5$? enter your answer in the box.

Explanation:

Step1: Substitute the values of a, b, c, d into the expression

We have \(a = 3\), \(b = 8\), \(c = 2\), \(d = 5\). Substitute these values into \(a^{2}+3b\div c - 2d\), we get \(3^{2}+3\times8\div2-2\times5\).

Step2: Calculate the exponentiation

First, calculate \(3^{2}\), according to the definition of exponentiation, \(3^{2}=3\times3 = 9\). So the expression becomes \(9 + 3\times8\div2-2\times5\).

Step3: Calculate the multiplication and division from left to right

Calculate \(3\times8\div2\) first. According to the order of operations (multiplication and division have the same precedence, so we calculate from left to right), \(3\times8 = 24\), then \(24\div2=12\). And calculate \(2\times5 = 10\). Now the expression becomes \(9 + 12-10\).

Step4: Calculate the addition and subtraction from left to right

First, \(9+12 = 21\), then \(21 - 10=11\).

Answer:

11