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what transformations were applied to \\(abcd\\) to obtain \\(abcd\\)? a…

Question

what transformations were applied to \\(abcd\\) to obtain \\(abcd\\)?

a. rotate 90 degrees counterclockwise about the origin, then translate 2 units up.
b. rotate 90 degrees counterclockwise about the origin, then translate 2 units down.
c. rotate 90 degrees counterclockwise about the origin, then translate 1 unit down.
d. rotate 180 degrees counterclockwise about the origin, then translate 1 unit down.

Explanation:

Identify coordinates of original and transformed vertices

Using the Geometric Rotations and Geometric Translations knowledge points

$$ LATEXBLOCK0 $$

Apply rotation transformation

Using the Geometric Rotations knowledge point

$$ LATEXBLOCK1 $$

Apply translation transformation

Using the Geometric Translations knowledge point

$$ LATEXBLOCK2 $$

This corresponds to a translation of 1 unit up. Let us re-verify the options.
Wait, let's re-examine the coordinates of \(A'\) and \(B'\) from the image:
Looking closely at the image:
The y-axis has labels: 2, 4, 6, 8.
The x-axis has labels: -2, -4, -6, -8.
Let's read the coordinates of \(A'\):
\(A'\) is at \(x = -5\), \(y = 3\).
\(B'\) is at \(x = -8\), \(y = 3\).
\(C'\) is at \(x = -8\), \(y = 7\).
\(D'\) is at \(x = -5\), \(y = 7\).

Let's check the options:
A. Rotate 90 degrees counterclockwise about the origin, then translate 2 units up.
B. Rotate 90 degrees counterclockwise about the origin, then translate 2 units down.
C. Rotate 90 degrees counterclockwise about the origin, then translate 1 unit down.
D. Rotate 180 degrees counterclockwise about the origin, then translate 1 unit down.

Wait, if we rotate 90 degrees counterclockwise, we get:
\(A(2,5)
ightarrow (-5, 2)\).
To get to \(A'(-5, 3)\), we must translate 1 unit UP. But option C says "translate 1 unit down".
Let's re-read the coordinates of the original figure \(ABCD\):
Is \(A\) at \((2, 5)\)?
Looking at \(ABCD\):
\(A\) is at \(x = 2\). The y-coordinate of \(A\) is at 5 (halfway between 4 and 6).
\(B\) is at \(x = 2\), \(y = 8\).
\(C\) is at \(x = 6\), \(y = 8\).
\(D\) is at \(x = 6\), \(y = 5\).
Wait, let's look at \(A'B'C'D'\):
Is \(A'\) at \((-5, 3)\)?
Looking at the y-axis for \(A'\) and \(B'\): they are at \(y = 3\) (halfway between 2 and 4).
Wait, if \(A'\) is at \(y = 3\), and the rotated point is at \(y = 2\), then we need to go UP 1 unit. Why is there no "translate 1 unit up" option?
Let's re-verify the rotation:
What if the rotation is clockwise?
\(R_{-90^\circ}(x, y) = (y, -x)\).
\(A(2,5)
ightarrow (5, -2)\). This is in Quadrant IV, but \(A'B'C'D'\) is in Quadrant II. So it must be counterclockwise (which goes from Quadrant I to Quadrant II).

Let's re-read the coordinates of \(ABCD\):
Could \(A\) be at \((2, 4)\)?
No, the line \(AD\) is clearly above 4. It is halfway between 4 and 6, so it is 5.
Could \(A'\) be at \(y = 4\)?
No, \(A'\) and \(B'\) are below 4, halfway between 2 and 4, so they are at 3.
Wait! What if the rotation is about a different point? The options all say "about the origin".
Let's check if there is a typo in the question's options or if we misread…

Answer:

  • (A) Rotate 90 degrees counterclockwise about the origin, then translate 2 units up.
  • (B) Rotate 90 degrees counterclockwise about the origin, then translate 2 units down.</mcq-correct>
  • (C) Rotate 90 degrees counterclockwise about the origin, then translate 1 unit down. (Correct answer)

<mcq-option>(D) Rotate 180 degrees counterclockwise about the origin, then translate 1 unit down.