Question

what is the theoretical probability of randomly picking a triangle from the shapes below?

Explanation:

Step1: Calculate total number of shapes

There are \(4\) triangles and \(2\) circles. Total number of shapes \(n = 4 + 2=6\).

Step2: Calculate probability of picking a triangle

Probability formula is \(P=\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}\). Number of favorable outcomes (triangles) \(m = 4\). So \(P=\frac{4}{6}=\frac{2}{3}\).

Answer:

\(\frac{2}{3}\)