Question

what is the statement for step 2 of the proof? ∠bac≅∠dac bc = dc △bac≅△dac ∠b≅∠d

Explanation:

Step1: Recall the definition of an angle bisector

Since \(AC\) is the angle bisector of \(\angle BAD\), by the definition of an angle bisector, it divides \(\angle BAD\) into two equal angles. So, \(\angle BAC=\angle DAC\).

Answer:

\(\angle BAC\cong\angle DAC\) (the first option)