Question

what are the solutions to the quadratic equation $x^2 - 16 = 0$?
$\bigcirc$ $x = 2$ and $x = -2$
$\bigcirc$ $x = 4$ and $x = -4$
$\bigcirc$ $x = 8$ and $x = -8$
$\bigcirc$ $x = 16$ and $x = -16$

Explanation:

Step1: Isolate \(x^2\)

Add 16 to both sides: \(x^2 = 16\)

Step2: Take square roots

\(x = \pm\sqrt{16} = \pm4\)

Answer:

x = 4 and x = -4