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Question
what are the solutions of \\(x^2 + 6x - 6 = 10\\)?
\\(x = -11\\) or \\(x = 1\\)
\\(x = -11\\) or \\(x = -1\\)
\\(x = -8\\) or \\(x = -2\\)
\\(x = -8\\) or \\(x = 2\\)
Rearrange the quadratic equation into standard form
$$
LATEXBLOCK0
$$
Factor the quadratic expression
$$
LATEXBLOCK1
$$
Solve for x
$$
LATEXBLOCK2
$$
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- \(x = -11\) or \(x = 1\)
- \(x = -11\) or \(x = -1\)
- \(x = -8\) or \(x = -2\)
- \(x = -8\) or \(x = 2\) (Correct answer)