Question

what is the solution to the system of equations shown below?
y = 2x + 3
3x + 2y = 20
(\square, \square)

Explanation:

Step1: Substitute \( y = 2x + 3 \) into \( 3x + 2y = 20 \)

Substitute \( y \) in the second equation: \( 3x + 2(2x + 3) = 20 \)

Step2: Simplify and solve for \( x \)

Expand: \( 3x + 4x + 6 = 20 \)
Combine like terms: \( 7x + 6 = 20 \)
Subtract 6: \( 7x = 14 \)
Divide by 7: \( x = 2 \)

Step3: Find \( y \) using \( y = 2x + 3 \)

Substitute \( x = 2 \): \( y = 2(2) + 3 = 7 \)

Answer:

\((2, 7)\)