Question

what is the solution to the equation $3 + sqrt4{4y} = 4$? options: $y = 4$, $y = \frac{1}{16}$, $y = \frac{1}{4}$, $y = 1$

Explanation:

Step1: Isolate the radical term

Subtract 3 from both sides.
$$3 + \sqrt[4]{4y} - 3 = 4 - 3$$
$$\sqrt[4]{4y} = 1$$

Step2: Eliminate the 4th root

Raise both sides to the 4th power.
$$(\sqrt[4]{4y})^4 = 1^4$$
$$4y = 1$$

Step3: Solve for y

Divide both sides by 4.
$$y = \frac{1}{4}$$

Answer:

$y = \frac{1}{4}$