Question

what is the probability of a heterozygous offspring for these two parents? 80% 50% 75%

Explanation:

Step1: Analyze the Punnett square

The Punnett square has four boxes. The parents are \( B \) and \( B \) (one parent) and \( B \) and \( b \) (the other parent). The combinations in the Punnett - square boxes are \( BB\), \( Bb\), \( BB\), \( Bb\).

Step2: Calculate the probability of heterozygous (\( Bb \))

The formula for probability is \( P=\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}\). The number of favorable outcomes (heterozygous \( Bb \)) is \( 2 \), and the total number of outcomes is \( 4 \). So \( P = \frac{2}{4}\).

Answer:

\( 50\%\)