Question

what is the probability that a data value in a normal distribution is between a z - score of - 1.32 and a z - score of - 0.34? round your answer to the nearest tenth of a percent.
#\tchoice
a.\t28.4%
b.\t29.4%
c.\t27.4%
d.\t26.4%
https://course.apexlearning.com/public/activity/9003003/assessment/preview
4/29
12/27/2020\tapex learning - courses
2b )
what is the probability that a data value in a normal distribution is between a z - score of - 1.42 and a z - score of - 0.34? round your answer to the nearest tenth of a percent.
#\tchoice
a.\t28.9%
b.\t29.9%
c.\t26.9%
d.\t27.9%

Explanation:

Step1: Encontrar la probabilidad para \(z = - 1.32\)

Usando la tabla de valores \(z\), \(P(z<-1.32)=0.0934\)

Step2: Encontrar la probabilidad para \(z = - 0.34\)

Usando la tabla de valores \(z\), \(P(z < - 0.34)=0.3669\)

Step3: Calcular la probabilidad entre los dos \(z - \)scores

\(P(-1.32<z<-0.34)=P(z < - 0.34)-P(z<-1.32)\)
\(P(-1.32<z<-0.34)=0.3669 - 0.0934=0.2735\)

Step4: Convertir a porcentaje

\(0.2735\times100 = 27.35\%\approx27.4\%\)

Step1: Encontrar la probabilidad para \(z=-1.42\)

Usando la tabla de valores \(z\), \(P(z < - 1.42)=0.0778\)

Step2: Encontrar la probabilidad para \(z=-0.34\)

Usando la tabla de valores \(z\), \(P(z < - 0.34)=0.3669\)

Step3: Calcular la probabilidad entre los dos \(z-\)scores

\(P(-1.42<z<-0.34)=P(z < - 0.34)-P(z < - 1.42)\)
\(P(-1.42<z<-0.34)=0.3669-0.0778 = 0.2891\)

Step4: Convertir a porcentaje

\(0.2891\times100=28.91\%\approx28.9\%\)

Answer:

C. \(27.4\%\)