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b) what will be the population in 6 years? p(6)=240(1.025)^{6} =278.3 w…

Question

b) what will be the population in 6 years?
p(6)=240(1.025)^{6}
=278.3 wolves
c) in how many years will the population double?
480 = 240(1.025)^{t}
2=(1.025)^{t}
t = \frac{2}{1.025}
t = 28.07 years
a certain culture of bacteria, triple every 25h. the initial count of present.
a) write an exponential function that models the given conditi

Explanation:

Step1: Use the exponential growth formula

The general form of an exponential growth formula is \(P(t)=P_0a^{t}\), where \(P_0\) is the initial amount, \(a\) is the growth factor, and \(t\) is the time. For bacteria that triple every \(25\) hours, if we let \(t\) be the time in hours, the formula is \(P(t)=P_0\times3^{\frac{t}{25}}\).

Answer:

\(P(t)=P_0\times3^{\frac{t}{25}}\)