Question

what is the output of this program? numa = 2 numb = 3 if numa == 2 or numb == 2: print(\yes\) elif numa == 2 and numb == 3: print(
o\) output:

Explanation:

Step1: Check if - condition

The condition numA == 2 or numB == 2 is checked first. Given numA = 2 and numB = 3, since numA == 2 is True, the 'or' condition is True.

Step2: Determine output

Since the first - if condition is True, the program will execute the print("yes") statement and skip the elif block.

Answer:

yes