Question

what number has 5 ten thousands, 3 more thousands than ten thousands, 7 fewer hundreds than thousands, the same number of tens as hundreds, and 5 fewer ones than thousands?

Explanation:

Step1: Determine ten - thousands place

The number of ten - thousands is 5. So the digit in the ten - thousands place is 5.

Step2: Determine thousands place

We know that the number of thousands is 3 more than the number of ten - thousands. Since the number of ten - thousands is 5, the number of thousands is $5 + 3=8$. So the digit in the thousands place is 8.

Step3: Determine hundreds place

The number of hundreds is 7 fewer than the number of thousands. Since the number of thousands is 8, the number of hundreds is $8-7 = 1$. So the digit in the hundreds place is 1.

Step4: Determine tens place

The number of tens is the same as the number of hundreds. Since the number of hundreds is 1, the number of tens is 1. So the digit in the tens place is 1.

Step5: Determine ones place

The number of ones is 5 fewer than the number of thousands. Since the number of thousands is 8, the number of ones is $8 - 5=3$. So the digit in the ones place is 3.

Now, we combine the digits from ten - thousands place to ones place: 5 (ten - thousands), 8 (thousands), 1 (hundreds), 1 (tens), 3 (ones). So the number is 58113.

Answer:

58113