Question

what number has 3 hundred thousands, no ten thousands, 4 more thousands than ten thousands, 4 more hundreds than ten thousands, 1 fewer ten than thousands, and 2 more ones than ten thousands?

Explanation:

Step1: Determine the digit in ten - thousands place

The problem states there are no ten - thousands, so the digit in the ten - thousands place (let's denote the place values: hundred thousands, ten thousands, thousands, hundreds, tens, ones) is \(0\).

Step2: Find the digit in thousands place

We know that there are 4 more thousands than ten thousands. Since the digit in ten - thousands place is \(0\), the digit in thousands place is \(0 + 4=4\).

Step3: Find the digit in hundreds place

There are 4 more hundreds than ten thousands. Since the digit in ten - thousands place is \(0\), the digit in hundreds place is \(0+4 = 4\).

Step4: Find the digit in tens place

There is 1 fewer ten than thousands. Since the digit in thousands place is \(4\), the digit in tens place is \(4-1=3\).

Step5: Find the digit in ones place

There are 2 more ones than ten thousands. Since the digit in ten - thousands place is \(0\), the digit in ones place is \(0 + 2=2\).

Step6: Find the digit in hundred - thousands place

The problem states there are 3 hundred thousands, so the digit in hundred - thousands place is \(3\).

Now, we write the number by combining the digits from the highest place value to the lowest:
Hundred - thousands: \(3\), Ten - thousands: \(0\), Thousands: \(4\), Hundreds: \(4\), Tens: \(3\), Ones: \(2\)

So the number is \(304432\).

Answer:

\(304432\)