Question

what is the length of a leg of an isosceles right - triangle whose hypotenuse measures 6 inches? let c represent the value of the hypotenuse. if the hypotenuse is c = a√2, then 6 = a√2. in inches, what is the value of a? 3 3√2 6 6√2

Explanation:

Step1: Recall isosceles right - triangle ratio

In an isosceles right - triangle, $c = a\sqrt{2}$, where $c$ is the hypotenuse and $a$ is the leg.

Step2: Solve for $a$

Given $c = 6$, then $6=a\sqrt{2}$. So, $a=\frac{6}{\sqrt{2}}=\frac{6\sqrt{2}}{2}=3\sqrt{2}$.

Answer:

$3\sqrt{2}$ inches