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what is the image of the point $(0,9)$ after a rotation of $90^{circ}$ …

Question

what is the image of the point $(0,9)$ after a rotation of $90^{circ}$ counterclockwise about the origin? answer attempt 1 out of 3

Explanation:

Step1: Recall the rotation rule

When a point \((x,y)\) is rotated \(90^{\circ}\) counter - clockwise about the origin, the new coordinates \((x',y')\) are given by the transformation \((x,y)\to(-y,x)\).

Step2: Apply the rule to the given point

For the point \((0,9)\), where \(x = 0\) and \(y=9\).
Substitute into the formula: \(x'=-y=-9\) and \(y'=x = 0\).

Answer:

\((-9,0)\)