Question

what happens to the current in a circuit if a 1.5 - volt battery is removed and is replaced by a 3 - volt battery?

Explanation:

Step1: Apply Ohm's Law

Ohm's Law is \(I=\frac{V}{R}\), where \(I\) is current, \(V\) is voltage, and \(R\) is resistance. Assume the resistance \(R\) of the circuit remains constant.

Step2: Analyze the change in voltage

Initially, \(V_1 = 1.5\space V\), so \(I_1=\frac{V_1}{R}=\frac{1.5}{R}\). After replacement, \(V_2 = 3\space V\), so \(I_2=\frac{V_2}{R}=\frac{3}{R}\).

Step3: Find the ratio of currents

\(\frac{I_2}{I_1}=\frac{\frac{3}{R}}{\frac{1.5}{R}}=\frac{3}{1.5} = 2\).

Answer:

The current in the circuit doubles.