Question

what is the gravitational attraction between the proton and electron in an hydrogen atom if they are ( 5.3\times10^{-11} ) meters apart? (( m_{\text{proton}} = 1.67\times10^{-27}\text{ kg}; m_{\text{electron}} = 9.11\times10^{-31}\text{ kg} ))
( 3.6\times10^{-25}\text{ n} )
( 3.6\times10^{25}\text{ n} )
( 3.62\times10^{-47}\text{ n} )
( 3.62\times10^{47}\text{ n} )

Explanation:

Step1: Recall the formula for gravitational force

The formula for gravitational force is \(F = G\frac{m_1m_2}{r^2}\), where \(G = 6.67\times10^{-11}\text{ N}\cdot\text{m}^2/\text{kg}^2\), \(m_1\) and \(m_2\) are the masses of the two objects, and \(r\) is the distance between them.

Step2: Substitute the given values

Substitute \(m_1 = 1.67\times 10^{-27}\text{ kg}\), \(m_2=9.11\times 10^{-31}\text{ kg}\), \(r = 5.3\times 10^{-11}\text{ m}\), and \(G = 6.67\times 10^{-11}\text{ N}\cdot\text{m}^2/\text{kg}^2\) into the formula:

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Answer:

C. \(3.62\times 10^{-47}\text{ N}\)