Question

what is the dr of the following first class lever? assume an ideal effort force (precision of 0.0)
effort
7.5 in
?
14 lbs
30 lbs
resistance

Explanation:

Step1: Recall the formula for a first - class lever

For a first - class lever, the principle of moments states $F_{e}d_{e}=F_{r}d_{r}$, where $F_{e}$ is the effort force, $d_{e}$ is the effort distance, $F_{r}$ is the resistance force, and $d_{r}$ is the resistance distance. We want to find the mechanical advantage (MA) or the force ratio (DR), and the formula for DR is $\text{DR}=\frac{F_{r}}{F_{e}}$.

Step2: Identify the values of $F_{r}$ and $F_{e}$

We are given that $F_{e} = 14$ lbs and $F_{r}=30$ lbs.

Step3: Calculate the DR

$\text{DR}=\frac{F_{r}}{F_{e}}=\frac{30}{14}\approx2.1$

Answer:

2.1