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Question
what conclusion can you draw from the following statements? - if a figure is a square, then it has four sides. - if a figure has four sides, then it is not a triangle. a. if a figure is not a triangle, then it is a square. b. if a figure has four sides, then it is a square. c. if a figure is a square, then it is not a triangle. d. if a figure is not a triangle, then it has four sides.
- Analyze the given statements:
- Statement 1: If a figure is a square, then it has four sides (let's denote \( p \): figure is a square, \( q \): figure has four sides, so \( p
ightarrow q \)).
- Statement 2: If a figure has four sides, then it is not a triangle (let's denote \( q
ightarrow r \), where \( r \): figure is not a triangle).
- By the law of syllogism, if \( p
ightarrow q \) and \( q
ightarrow r \), then \( p
ightarrow r \).
- Evaluate each option:
- Option A: Just because a figure is not a triangle (\( r \)), we can't conclude it's a square (\( p \)). There are other figures with four sides (like rectangles, parallelograms) or more/less sides that are not triangles. So A is incorrect.
- Option B: Having four sides (\( q \)) doesn't mean it's a square. There are many quadrilaterals (e.g., rectangles, trapezoids) that are not squares. So B is incorrect.
- Option C: From the syllogism, if a figure is a square (\( p \)), then it has four sides (\( q \)) and if it has four sides (\( q \)), then it's not a triangle (\( r \)). So if a figure is a square, then it is not a triangle (\( p
ightarrow r \)). This is correct.
- Option D: Just because a figure is not a triangle (\( r \)), we can't conclude it has four sides. A pentagon is not a triangle and has five sides. So D is incorrect.
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C. If a figure is a square, then it is not a triangle