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Question
what is the center of a circle represented by the equation (x + 9)^2+(y - 6)^2=10^2? (-9,6) (-6,9) (6,-9) (9,-6)
Step1: Recall circle - equation formula
The standard form of a circle equation is $(x - a)^2+(y - b)^2=r^2$, where $(a,b)$ is the center of the circle and $r$ is the radius.
Step2: Rewrite the given equation
The given equation is $(x + 9)^2+(y - 6)^2=10^2$, which can be rewritten as $(x-(-9))^2+(y - 6)^2=10^2$.
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A. $(-9,6)$