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what is the best approximation for the perimeter of the pentagon abcde?…

Question

what is the best approximation for the perimeter of the pentagon abcde? 25 units 17 units 22 units 54 units

Explanation:

Step1: Find the length of each side using the distance formula \(d = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}\)

  • For \(EA\): \(E(0,0)\), \(A(3,4)\)

\(EA=\sqrt{(3 - 0)^2+(4 - 0)^2}=\sqrt{9 + 16}=\sqrt{25}=5\)

  • For \(AB\): \(A(3,4)\), \(B(6,3)\)

\(AB=\sqrt{(6 - 3)^2+(3 - 4)^2}=\sqrt{9+1}=\sqrt{10}\approx3.16\)

  • For \(BC\): \(B(6,3)\), \(C(8,0)\)

\(BC=\sqrt{(8 - 6)^2+(0 - 3)^2}=\sqrt{4 + 9}=\sqrt{13}\approx3.61\)

  • For \(CD\): \(C(8,0)\), \(D(2,-3)\)

\(CD=\sqrt{(2 - 8)^2+(-3 - 0)^2}=\sqrt{36+9}=\sqrt{45}\approx6.71\)

  • For \(DE\): \(D(2,-3)\), \(E(0,0)\)

\(DE=\sqrt{(0 - 2)^2+(0+3)^2}=\sqrt{4 + 9}=\sqrt{13}\approx3.61\)

Step2: Sum up the lengths of all sides

\(P=EA + AB+BC + CD+DE\)
\(P\approx5+3.16 + 3.61+6.71+3.61\)
\(P\approx22\)

Answer:

22 units