Question

what is the area, in square meters, of the isosceles trapezoid below? 5.8 m 5.8 m 15.8 m

Explanation:

Step1: Recall area formula

$A=\frac{(b_1 + b_2)h}{2}$, where $b_1,b_2$ are bases and $h$ is height.

Step2: Identify values

$b_1 = 5.8$ m, $b_2=15.8$ m, $h = 5.8$ m.

Step3: Substitute values

$A=\frac{(5.8 + 15.8)\times5.8}{2}$.

Step4: Calculate sum of bases

$5.8+15.8 = 21.6$ m.

Step5: Multiply by height

$21.6\times5.8=125.28$ square - meters.

Step6: Divide by 2

$A=\frac{125.28}{2}=62.44$ square meters.

Answer:

$62.44$ square meters