Question

what is the area, in square inches, of the isosceles trapezoid below?

Explanation:

Step1: Recall area formula

The formula for the area of a trapezoid is $A=\frac{(b_1 + b_2)h}{2}$, where $b_1$ and $b_2$ are the lengths of the bases and $h$ is the height.

Step2: Identify values

Here, $b_1 = 6.4$ in, $b_2=16$ in and $h = 5.2$ in.

Step3: Substitute values

$A=\frac{(6.4 + 16)\times5.2}{2}$.
First, calculate the sum of the bases: $6.4+16 = 22.4$ in.
Then, multiply by the height: $22.4\times5.2=116.48$ square - inches.
Finally, divide by 2: $A=\frac{116.48}{2}=58.24$ square - inches.

Answer:

$58.24$ square inches