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what is the approximate value of y - x? 4.9° 6.2° 11.1° 17.2°

Question

what is the approximate value of y - x?
4.9°
6.2°
11.1°
17.2°

Explanation:

Step1: Find the value of \(x\)

In right - triangle \(NL M\), \(\tan x=\frac{ML}{NL}\). Given \(NL = 19.1\) in and \(ML=14.1\) in.
\(\tan x=\frac{14.1}{19.1}\)
\(x=\arctan(\frac{14.1}{19.1})\)
Using a calculator, \(x\approx36.5^{\circ}\)

Step2: Find the value of \(y\)

In right - triangle \(NL M\), \(\tan y=\frac{NL}{ML}\)
\(\tan y=\frac{19.1}{14.1}\)
\(y = \arctan(\frac{19.1}{14.1})\)
Using a calculator, \(y\approx53.7^{\circ}\)

Step3: Calculate \(y - x\)

\(y - x\approx53.7^{\circ}-36.5^{\circ}\)
\(y - x\approx17.2^{\circ}\)

Answer:

\(17.2^{\circ}\)