Question

the weights of the chocolate in hershey kisses are normally distributed with a mean of 4.5338 g and a standard deviation of 0.1039 g.
a. for the bell - shaped graph of the normal distribution of weights of hershey kisses, what is the area under the curve?
b. what is the value of the median?
c. what is the value of the mode?
d. what is the value of the variance?
a. for the bell - shaped graph of the normal distribution of weights of hershey kisses, what is the area under the curve?
1 (type an integer or a decimal. do not round.)
b. what is the value of the median?
g (round to four decimal places as needed.)

Explanation:

Step1: Properties of normal distribution

In a normal distribution, the mean, median, and mode are equal. Given the mean \(\mu = 4.5338\) g.

Step2: Calculate the variance

The variance \(\sigma^{2}\) is the square of the standard deviation \(\sigma\). Given \(\sigma=0.1039\) g, so \(\sigma^{2}=(0.1039)^{2}\)

Answer:

a. \(1\)
b. \(4.5338\) g
c. \(4.5338\) g
d. \((0.1039)^{2}=0.0108\) g²